New Things to Learn

• coding through 2.7.10 tutorial
• Something Learned
  • if statement
  • for statement
  • the range() function
    • range(5, 10, step) 值得注意的是取数乃是这样的 范围[ ) step 默认为1
    • range() 与list的结合
      • 简化为：for i, v in enumerate(['Mary', 'had', 'a', 'litter', 'lamb']):
  • break and continue statement
    • break 是哪里 打破 最近的 Loops
    • continue 又是继续的哪里 最近的 Loops
  • else 不要受制于 matlab 的else Python的else可用于Loops
  • pass statement
  • Define functions 与c中的类似
    • default argument values
    • Keyword arguments 这个比较鲜活

新知

def cheeseshop(kind, *arguments, **keywords):
    print '-- do you have any', kind, "?"
    print "-- I am sorry, we're all out of", kind
    for arg in arguments:
        print arg
    print '-' * 40
    keys = sorted(keywords.keys())
    for kw in keys:
        print kw, ":", keywords[kw]

cheeseshop("limburger", "it's very runny, sir.", "It's really very, Very runny, sir.", shopkeeper = 'Michael Palin', client = 'John Cleese', sketch = 'cheese shop sketch')

• *name01 与 **name02 先后顺序
• 涉及 dictionary 还未细看 下一步着手
• keys = sorted(keywords.keys())

• 看输出结果

    -- do you have any limburger ?  
    -- I am sorry, we're all out of limburger  
    it's very runny, sir.  
    It's really very, Very runny, sir.  
  
    client : John Cleese   
    shopkeeper : Michael Palin  
    sketch : cheese shop sketch
  

  • 明白
  • 但是为什么呢？
    • kind 参数 只能是第一个 "limburger"
    • *arguments 参数 "it's very runny, sir.", "It's really very, Very runny, sir.
    • **keywords 参数 其他剩余
  • keys = sorted(keywords.keys()) 不明白 进一步需要了解 Dic 再回来 看这个 confused codes
• When ?
• How to use them?

Next

• [] dictionary dive in 官方help and 问题
• [] 4.7.3 Arbitrary Argument Lists
• [] 4.7.4 Unpacking Argument Lists
• [] 4.7.5. Lambda Expressions
• [] 4.7.6. Documentation Strings
• [] 4.8 Intermezzo: Coding Style

SUM

• Coding 下去
• 7个蕃茄学习 1个蕃茄整理
• 反思
  • 代码练了 没有去完成一个项目 自定义的项目 发现还是不怎么入脑
  • 那么的思考 完成一个 怎样有趣的项目 如同show me the code的 learn by doing
  • 这么个循序渐进额可以

今日代码